If such an element exists, the function returns its index otherwise, it returns (-insertionPoint - 1) where insertionPoint is the index where this element should be inserted so that the list remains sorted. To search an element in a sorted list, call the binarySearch() function passing the value as an argument. It works significantly faster than other built-in search functions but requires the list to be sorted in ascending order according to a certain ordering: natural or another one provided in the function parameter. There is one more way to search elements in lists – binary search. I read some articles and I know this error related to the invalid index, but I used the "indices" key and I think it's pretty safe.Println(numbers.indexOfLast ) In above code, I have error at the "alphabet.removeAt(j)" command, so I try another command to print out the characters instead of delete them, and it runs fine. I want to delete any character from the alphabet which show up in the string. Let's say I have a string (it was optimized to NOT have any duplicated character), i want to compare all characters in that string to the alphabet, which declared as a mutable List of character. I'm newbie to Kotlin, and new to programming also, so pls be gentle :)
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